X^2+112x=0

Solution for X^2+112x=0 equation:

X^2+112X=0

a = 1; b = 112; c = 0;
Δ = b2-4ac
Δ = 1122-4·1·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-112}{2*1}=\frac{-224}{2}
=-112
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+112}{2*1}=\frac{0}{2}
=0
$